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7n^2-28n-28=0
a = 7; b = -28; c = -28;
Δ = b2-4ac
Δ = -282-4·7·(-28)
Δ = 1568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1568}=\sqrt{784*2}=\sqrt{784}*\sqrt{2}=28\sqrt{2}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28\sqrt{2}}{2*7}=\frac{28-28\sqrt{2}}{14} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28\sqrt{2}}{2*7}=\frac{28+28\sqrt{2}}{14} $
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